Matematică
HabarNuAmDeNume
13

Sa se determine a,b astfel incat: a)[latex] \lim_{n \to \infty} ( \frac{ an^{2} +bn+2}{bn^{2}+4n+3} )^{ \frac{ n^{2} }{n+1} } = \frac{1}{e} [/latex] b)[latex] \lim_{n \to \infty} ( \sqrt{ n^{2}+n+1 }- \sqrt{ n^{2}+an+2} ) ^{ \frac{b n^{2}+n }{n+1} } = \frac{1}{e} [/latex] c)[latex] \lim_{n \to \infty} (1+ \frac{ n^{2} +an+1}{n^{2}+3n-2} )^{n} = e[/latex] d)[latex] \lim_{n \to \infty} n( \sqrt[n]{a}- \sqrt[2n]{a} )=1 , a\ \textgreater \ 0[/latex]

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(1) Răspunsuri
tabakrumery

Ti-am atasat solutia la a) ;)

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