Matematică
natybuliga
1

Media geometrică a numerelor a=✓3-1÷2 b=✓3+1

+0
(2) Răspunsuri
ruxandraruxi39

Mg=√a·b Mg=√(√3-1)·√(√3+1)/2=√(3-1)/√2=√2/√2=1

sonia06

[latex]\it m_g = \ \sqrt{a\cdot b} = \sqrt{\dfrac{\sqrt3-1}{2}\cdot(\sqrt3+1)} = \\\;\\ \\\;\\ = \sqrt{\dfrac{(\sqrt3-1)(\sqrt3+1)}{2}} = \sqrt{\dfrac{3-1}{2}} = \sqrt{\dfrac{2}{2}} =1[/latex]

Adaugă răspuns