In triunghiul ABC, MN paralel cu BC. M apartine AB,N apartine AC. AM = 4 CM MB=X-1 AN=6 CM NC=X+1. Aflati latura AB,AC.
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conditie x - 1 > 0 ; x >1 MN II BC ⇒ Δ AMN ≈ Δ ABC AM / MB = AN / NC 4 / ( x -1) = 6 / ( x + 1) 4· ( x +1) = 6·( x -1) 4x + 4 = 6x - 6 4 + 6 = 6x - 4x ; 10 = 2x x = 5 AB = AM + MB= 4cm + ( 5 -1) cm = 8 cm AC = AN + NC = 6cm + ( 5 + 1) cm = 12 cm
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