1)impartind suma a 3 nr consecutive la 5 obtinem catul 8 si restul 3 .Aflati nr

notam nr consecutive cu a, a+1, a+2 deci (a+a+1+a+2):5=8,3 deci avem (3a+3):5=8,3 => 3a+3=8x5+3. deci 3a+3=43. 3a=40,  deci a =13.33, b=13.33+1 => b=14.33 si c=15.33.