Matemática
faraujobittenc
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utilizando a propriedade das potencias, determine (0,5)².(0,5)⁻⁷ (0,5)⁻² 12⁻⁶ 12⁶

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amandadearaujo

[latex]a) \frac{(0,5)^2.(0,5)^{-7}}{(0,5)^{-2}}= \\ \\ \frac{(0,5)^{2+(-7)}}{(0,5)^{-2}}= \\ \\ \frac{(0,5)^{-5}}{(0,5)^{-2}} \\ \\ (0,5)^{-5-(-2)}=(0,5)^{-3}\\ou(continuando)\\(0,5)^{-3}= \\\\ (\frac{1}{2})^{-3}=\\\\2^3=8\\\\\\b) \frac{12^{-6}}{12^6}=\\\\12^{-6-6}=12^{-12}\\\\\\\\Renato.[/latex]

Laarissa

(0,5)².(0,5)⁻⁷  = (0,5)^(2-7+2) = (0,5)^ - 3 (0,5)⁻² 12⁻⁶  = 12^(-6-6) ==> 12^-12 12⁶

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