Matemática
Tai16
2

Determine o 13° termo da P.G. (64,32,16,...).

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Conta apagada

[latex]a1=64\\a2=32\\\\r=\frac{a2}{a1}=\frac{32}{64}=\frac{1}{2}\\\\an=a1.q^{n-1}\\\\a13=64.(\frac{1}{2})^{12}=64.\frac{1}{2.2.2.2.2.2.2.2.2.2.2.2}=64.\frac{1}{16.16.16}=\boxed{\frac{1}{64}}[/latex]

eduardoducatti

a13= ? q= 32/64= 1/2 a1= 64 = 2^6 n=12 a13= a1.q^12 a13= 2^6.1/2^12 a13= 2^(6-12) a13= 2^-6 a13= 1/2^6= 1/64

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