3[1/3]*1[3/5]-2[5/6] 1-8/15:24/25 pomiędzy 1 a 3 jest kreska ulamkowa proszę o pilną odpowiedz

[latex]3\frac{1}{3}*1\frac{3}{5}-2\frac{5}{6}=\frac{10}{3}*\frac{8}{5}-2\frac{5}{6}=\frac{16}{3}-2\frac{5}{6}=5\frac{1}{3}-2\frac{5}{6}=5\frac{2}{6}-2\frac{5}{6}=4\frac{8}{6}-2\frac{5}{6}=2\frac{3}{6}=2\frac{1}{2}[/latex] [latex]1-\frac{8}{15}:\frac{24}{25}=1-\frac{8}{15}*\frac{25}{24}=1-\frac{5}{9}=\frac{4}{9}[/latex]

3  1/3 x 1  3/5 - 2  5/6 = 10/3 x 8/5 - 2  5/6  = 16/3 - 2  5/6 = 5  1/3 - 2  5/6 = 5  2/6 - - 2  5/6 = 4  8/6 - 2  5/6 = 2  3/6 = 2  1/2   1 - 8/15 : 24/25 = 1 - 8/15 x 25/24 = 1 - 5/9 = 4/9