Mathematics
jazzyklinock
3

Which of ordered pairs is not a function? 1) {(0,9),(9,0),(1,2),(3,4)} 2) {(0,1),(-1,0),(1,2),(3,2)} 3) {(2,3),(3,4),(4,5),(5,6)} 4) {(2,3),(2,4),(4,5),(4,6)}

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(2) Answers
Browneyes

4 is not a function because one argument (element of x set) may have only one value (element of y set). Here in 4 optiton you can see that "2" have also value "3" and value "4" what is impossible in function.

Polieke

[latex]for\ one\ argument\ is\ exactly\ one\ value\ of\ the\ function\\ \\in\ 4)\\\\ x=2\ \ \Rightarrow\ \ (y=3\ \ and\ \ y=4)\ \ \ \leftarrow\ \ contradiction\\\\ x=4\ \ \Rightarrow\ \ (y=5\ \ and\ \ y=6)\ \ \ \leftarrow\ \ contradiction\\ \\Ans.\ not\ functions\ are\ pairs: (2,3)\ and\ (2,4);\ \ \ (4,5)\ and\ (4,6)[/latex]

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