Dean97
6

# What is the maximum mass of methane (CH4) that can be burned if only 1.0 g of oxygen is available and how do you figure it out?

Make the reaction: $CH_4+2O_2=CO_2+2H_2O$ For 2*32=64 grams of oxygen, you can burn 2*16=32 grams of methane (that is, half). So, our answer is .5g. Other intermediate calculations are mollecular masses: $\mu_{CH_4}=A_C+4A_H=12+4=16 \\ mu_{O_2}=2A_O=2*16=32$