The volume of a sample of gas at 273 K is 100.0 L. If the volume is decreased to 50.0 L at constant pressure, what will be the new temperature of the gas?
Ideal gas equation is PV = nRT. V/T = nR/P = constant. Therefore, (V/T)initial = (V/T)final. 100/273 = 50/T T = 50 x 273/100=136.5 K. Hope this helps!