Mathematics
CheryleSolorio820
4

The faces of a green tetrahedron die are marked 10,20,30 and 40. All three die are thrown together and the scores added. Find the probability that the total is more than 30 but less than 35.

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(2) Answers
hanan1

Assuming all three die are identical...  ways to get 30  40, any two others  30, and any two others  20, and any two others  10, and any two others, one of which is greater than 10.  So the probablity of getting greater than 30 is  Pr(>30)=1-pr(three 10s)=1-1/4 ^3  ways of getting less than 35  three 10's  Well, that sort of messes things up for getting over 30..  so Pr ( 30

gionnawaters11

Hello there. The faces of a green tetrahedron die are marked 10,20,30 and 40. All three die are thrown together and the scores added. Find the probability that the total is more than 30 but less than 35. Pr(>30)=1-pr(three 10s)=1-1/4 ^3  Pr ( 30

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