Mathematics
mwyche23
8

solve x^2+4x+3=0                                          solve the equation and simplify

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Gracie216

[latex]x^2+4x+3=0 \\ \\\Delta = b^{2}-4ac = 4^{2}-4*1* 3= 16-12=4 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-4-\sqrt{4}}{2}=\frac{-4-2}{2}=\frac{-6}{2}=-3 \\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-4+\sqrt{4}}{2}=\frac{-4+2}{2}=\frac{-2}{2}=-1\\ \\Answer : \ x=-1 \ \ or \ \ x=-3[/latex]

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