Solutions First Lets solve for this equation [latex]6x + 3y = -6 [/latex] [latex]6x + 3y = -6 [/latex] [latex]6x+3(-2-2x)=-6 [/latex] [latex]-6=-6[/latex] Therefore this given equation is a dependent system. Solve for [latex]2x + y = -2[/latex] [latex]2x+y=-2[/latex] [latex]y=-2-2x [/latex] There are too many solutions to these equations.

6x + 3y = -6 2x + y = -2 Solve both equations for the same variable, in this case, I'll solve for y. 2x + y = -2 Subtract 2x from both sides y = -2x -2 6x + 3y = -6 Subtract 6x from both sides 3y = -6x -6 Divide both sides by 3 y = -2x -2 Once you have them solved you can set them equal to each other and solve. -2x -2 = -2x -2 But, these two equations are the same, so any number you put in for x will work. The answer to the system is infinite solutions.