Mathematics
Joejoe26
26

Solve the following problem. show all steps (V.E.S.T.) The sum of three numbers is 26. The second number is twice the first and the third number is 6 more than the second. Find the numbers.?.

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(2) Answers
bbb911

we have three numbers: first number=x second number=2x third number=2x+6 we can suggest this equation: x+2x+(2x+6)=26 x+2x+2x=26-6 5x=20 x=20/5 x=4 First number=x=4 second number=2x=2(4)=8 third number=2x+6=2(4)+6=8+6=14 Answer: the numbers are 4, 8 and 14.

Miraclehug

The sum of three numbers is 26."  x+y+z = 26  "the second number is twice the first"  y = 2x  "the third number is 6 more than the second"  z = 6+y  You have the system of equations  x + y + z = 26  2x - y = 0  -y + z = 6  Solve using Gauss-Jordan Elimination:  x+y+z = 26  -3y-2z = -52  -y+z = 6  x+y+z = 26  y+(2/3)z = 52/3  -y+z = 6  x+(1/3)z = 26/3  y+(2/3)z = 52/3  (5/3)z = 70/3  x+(1/3)z = 26/3  y+(2/3)z = 52/3  z = 14  x = 4  y = 8  z = 14 

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