Solve 6 3- x =6 2 for x.
A. x = 1 B. x = 9 C. x = -6 D. x = - 1

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(2) Answers

sshotts

−x+63=62xStep 2: Subtract 62x from both sides.−x+63−62x=62x−62x−63x+63=0Step 3: Subtract 63 from both sides.−63x+63−63=0−63−63x=−63Step 4: Divide both sides by -63.−63x−63=−63−63x=1there for x=1

Kecialongino

is there sops to be a multiplication sine between 6 , 3 and 6 , 2 ?