Mathematics
secrethippo
18

please help!!!!!!!!! Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.

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(1) Answers
Derrick934

Solution:First integer = x Second integer = x + 2 Third integer = x + 4 Since four times the first integer equals six more than the product of two and the third integer. => 4x = 6 + 2(x + 4) => 4x = 6 + 2x + 8 => 2x = 14 => x = 7. Hence, First integer = x = 7 Second integer = x + 2 = 7 + 2 = 9 Third integer = x + 4 = 7 + 4 = 11.

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