Nancy is playing on a ladder and slide. The entry point of the slide is 3.0 meters above the ground and the slide is inclined at an angle of 30.0° with the horizontal. What is Nancy’s displacement each time she slides down from the top?

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The problem can be solved with a trigonometric analysis. Since the question gives away the fact that the slide is 3 meters above the ground, and is include at an angle of 30 degrees, we can create an image with the slide forming a triangle. Obtaining the displacement (hypotenuse of the created image), we take the sine of the angle: sin 30 = 3/s where: s = displacement s = 3 / sin 30 s = 6 Therefore, Nancy's displacement is 6 m each time she slides down from the top.

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