Juan is thinking of two numbers. He says that 3 times the first number minus the second number is 118. In addition, two times the first number plus the second number is 147. Find the numbers.

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We will call the first number n, and the second number x. 3n-x=118 2n+x=147 Now, solve one of the equations for x. x=147-2n Then, substitute this into the other formula for x.  3n-(147-2n)=118 Next, solve for n: 3n-147+2n=118 5n=265 n=53 ^^^That's your first number. Lastly, plug in 53 for n into either equation to solve for x. 2(53)+x=147 106+x=147 x=41 ^^^This is your second number.

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