Physics
Owen882
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Is v2 = v1t+a dimensionally correct? Explain please!

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giudobieber63

you want v2 = v1 + at v is measured in m/s, a in m/s2, and t in s. the dimensions multiply like algebraic quantities.  so because v2 is measured in m/s, then (v1 + at) has to come out in m/s  the units for (v1 + at) are (m/s) + (m/s2)(s) time "s" cancels out one acceleration "s", so it comes ut to (m/s) + (m/s), which = (m/s).  if you had (v1t + a), then you would have (m/s)(s) + (m/s2) which = (m) + (m/s2), which doesn't work.

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