Mathematics
paul2
5

I just want to know how to set up.  Cara is preparing an acid solution. She needs 200 milliliters of 48% concentration solution. Cara has 60% and 40% concentration solutions in her lab. How many milliliters of 40% acid solution should be mixed with 60% acid solution to make the required amount of 48% acid solution?  Okay so these are the two equations I was trying. Where x=milliliters of 60% solution and y=milliliters of 40 percent solution  X+Y=200  .6X+.4Y=200(.48)  Thanks so much!!

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(1) Answers
anyacanary

The answer is in the attachment .........................................................

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