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[latex]x^2+3xy+y^3=10\\2x+3xy'+3y+2yy'=0\\(2x+3y)+(3xy'+2yy')=0\\2x+3y+(3x+2y)y'=0\\(3x+2y)y'=-2x-3y\ /\ :\ (3x+2y)\\y'=\frac{-2x-3y}{3x+2y}[/latex]
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[latex]x^2+3xy+y^3=10\\2x+3xy'+3y+2yy'=0\\(2x+3y)+(3xy'+2yy')=0\\2x+3y+(3x+2y)y'=0\\(3x+2y)y'=-2x-3y\ /\ :\ (3x+2y)\\y'=\frac{-2x-3y}{3x+2y}[/latex]