Mathematics
DaciaMassengill60
20

How do you solve, 2=2y-x and 23=5y- 4x , using the substitution method

+2
(1) Answers
BeatrizBeatley889

2= 2y - x 23 = 5y - 4x isolate the x in the first equation x = 2y - 2 now use this to substitute x in the second equation 23 = 5y - 4 (2y - 2) 23 = 5y - 8y + 6 23 = -3y + 6 -3y = 17 y = -5 2/3 (5.6 repeating ) now use that to find x in either equation. 2 = 2 (-5.66666) - x 2= -11.3 repeating - x 13.3 repeating = -x x = -13.3 repeating optional ** use the second equation to check

Add answer