Mathematics
Greek796
2

How do I solve 5 (y-2) +6=21

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(2) Answers
lyssie11234

[latex]5(y-2)+6=21\\\\5\cdot y-5\cdot2+6=21\\\\5y-10+6=21\\\\5y-4=21\ \ \ /+4\\\\5y-4+4=21+4\\\\5y=25\ \ \ /:5\\\\5y:5=25:5\\\\y=5[/latex]

bohancecilia

5( y - 2) + 6 = 21 Multiply 5 into the Parentheses  = 5y - 10 + 6 = 21 Subtract 6 on both sides 10 - 6  , and 6 - 6 = 5y - 4 = 21 Add 4 to both sides to get rid of 4. - 4 + 4 , and 21 + 4 = 5y = 25 Divide by 5 . 5y/5 and 25/5 = (y = 5)

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