janicespruill
25

# How do I find the surface area of the figure? Thank you.

It's the sum of areas of: two identical trapezoids     $A_1=\frac{a+b}2\cdot h$ a=6+8=14 in. b=6 in. h=6 in. and rectangle $A_2=w\cdot l$ $w=2\frac12 in. \\l=6+6+6+8+10 = 36 in.$ $A=2A_1+A_2=2\cdot\frac{a+b}2\cdot h+w\cdot l=(a+b)\cdot h+w\cdot l\\\\A=(14+6)\cdot 6+2\frac12\cdot 36= 120+90=210in.^2=1354.836cm^2\approx1355cm^2$