Help with this pleas
For an equation of a line in slope intercept form y = mx+b, m is the slope and b is the y-intercept. In the equation y = (-3/4)x + 3, the value of b here is 3, so 3 is the y-intercept. So the line should go through (0,3).
Simple, you have y=-3/4x+3 Your y-intercept is 3. So it's at (0,3) Then the -3/4 it basically means go down three points and go over four points. So after (0,3) it's (4,0) then (8,-3) and so on. Going positive it's (-4,6) then (-8,9) And so on and so forth.