f(x) = 4x 3 - x 2 + 1 g(x) = x - 1 f(g(2)) solve for g (2) 2-1=1 solve for f (x) 4 (1)^3-(1)^2+1 4-1+1 4

[latex] f(x)=4x^3-x^2+1 \\ \\ g(x)=x-1 \\ \\ f(g(2-1))=f(1) \\ \\ =4(1)^3-(1)^2+1 \\ \\ =4(1)^3-( 1)^2+1 \\ \\ =4-1+1 \\ \\ =4 [/latex]