# Give all solutions if the nonlinear system of equations, including those with no real complex components. y=x^2+6x 4x-y=-24

y=x^2+6x Apply the value of y into the equation below: 4x-y=-24 4x-(x^2+6x) = -24 4x-x^2-6x = -24 x^2+2x-24=0 (x+6)(x-4)=0 Therefore x can be -6 or 4 If x = -6 Then y = (-6)^2+6(-6) = 36 -36=0 If x = 4 Then y = (4)^2 + 6(4) = 16 + 24 = 40

[latex]\left\{\begin{array}{ccc}y=x^2+6x\\4x-y=-24\end{array}\right\\\\substitute:\\\\4x-(x^2+6x)=-24\\\\4x-x^2-6x+24=0\\\\-x^2-2x+24=0\\\\a=-1;\ b=-2;\ c=24\\\\\Delta=b^2-4ac[/latex] [latex]\Delta=(-2)^2-4\cdot(-1)\cdot24=4+96=100\\\\x_1=\frac{-b-\sqrt\Delta}{2a};\ x_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{100}=10\\\\x_1=\frac{2-10}{2\cdot(-1)}=\frac{-8}{-2}=4;\ x_2=\frac{2+10}{2\cdot(-1)}=\frac{12}{-2}=-6\\\\y_1=4^2+6\cdot4=16+24=40;\ y_2=(-6)^2+6\cdot(-6)=36-36=0\\\\Answer:\\x=4\ and\ y=40\ or\ x=-6\ and\ y=0[/latex]