Mathematics
jariuscook
3

f(x)=(x+1)√2+x maka f'(x)  adalah ...

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(2) Answers
Brittneyy

 f'(x) = [ (x+1)√2+x  ]' = [ (x+1)√2 ] ' + x ))' = ( x + 1) ' * [latex] \sqrt{2} [/latex] + x ' = ( x ' + 1 ' )[latex] \sqrt{2} [/latex] + x ' = [latex] \sqrt{2} [/latex] + 1.

lyssie11234

[latex]f(x)=(x+1)\sqrt{2+x}\\\\f'(x)=(x+1)'\cdot\sqrt{2+x}+(x+1)\cdot(\sqrt{2+x})'\\\\=1\cdot\sqrt{2+x}+(x+1)\cdot\frac{1}{2\sqrt{2+x}}\cdot1=\sqrt{2+x}+\frac{x+1}{2\sqrt{2+x}}\\\\\\D_f:x\geq-2\\\\D_{f'}:x > -2[/latex]

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