Mathematics
charbsb
19

Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.

+1
(1) Answers
Harley24

First integer = x Second integer = x + 2 Third integer = x + 4 Since four times the first integer equals six more than the product of two and the third integer. => 4x = 6 + 2(x + 4) => 4x = 6 + 2x + 8 => 2x = 14 => x = 7. Hence, First integer = x = 7 Second integer = x + 2 = 7 + 2 = 9 Third integer = x + 4 = 7 + 4 = 11. Hope it helps

Add answer