Mathematics
MikMik
19

Four times the first of three consecutive even integers is six more than the product of two and the third integer. Find the integers.

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(1) Answers
Aleeah67

Assume the first integer is x, then the rest two are x+2, x+4 So 4x - 6 = (x+2)(x+4) -> 4x - 6 = x^2 + 6x + 8 -> x^2 + 2x + 14 = 0 Not sure if there are problems with your question description, but apparently no real solutions are possible here.

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