find two consecutive numbers with a product of 121

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(1) Answers

lily5

One number: x
Its consecutive: x + 1
Product:
x(x+1)=121
x² + x - 121 = 0
Δ = 1² - 4.1.(-121)
Δ = 1+484
Δ = 485
As square root of 485 is not integer, do not exist two consecutive numbers with product of 121