Mathematics
luismeza722
2

Find the area of a parrallelogram, b=(-4r^-2)2 h=(-6r^4z^2)^-1

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armmermom2x

The formula for the area of the parallelogram is base x height so the base is (-4r^-2)2 while the height is (-6r^4z^2)^-1 -4r^-2can be written as -4/r^2 while the height can be written as -6r^-4z^-2 or -6/r^4z^2 So: A=bh A=(-4/r^2)2(-6/r^4z^2) A=48/r^6z^2. Hope this helps  

Polieke

[latex]A=b\cdot h\\\\b=(-4r^{-2})^2=(-4)^2\cdot (r^{-2})^2=16\cdot r^{-4}\\\\h=(-6\cdot r^4\cdot z^2)^{-1}=(-6)^{-1}\cdot (r^4)^{-1}\cdot (z^2)^{-1}=- \frac{1}{6}\cdot r^{-4}\cdot z^{-2}\\ \\ \\A= 16\cdot r^{-4}\cdot (- \frac{1}{6})\cdot r^{-4}\cdot z^{-2}=- \frac{8}{3}\cdot r^{-4-4}\cdot z^{-2} =- \frac{8}{3}\cdot r^{-8}\cdot z^{-2}[/latex]

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