Calculate the PH of 0.25mol H2SO4
Ka= 1.9 x 10-5
only have experience with simpler ones like KOH, the H2SO4 is whats confusing me

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(1) Answers

Peanut2

This problem uses the relationship between Ka and the concentrations of the ions. Calculations are as follows:
1.9 x 10-5= x^2 / (0.25 - x)
x is very small and the denominator is approximately equal to 0.25. Thus, x is 2.2 x 10^-3
pH = -log (2.2 x 10^-3) = 2.66