Physics
Janning247
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Calculate the force between a 0.05 C charge and a 0.03 C charge 2 meters apart.

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(1) Answers
bharoo

E=kq/r^2 k=9x10^9 E1=k 0.05/1^2=0.05k E2=k 0.03/1^2=0.03k the resultant of the force is 0.05k-0.03k= 0.02k=18x10^7 towards the 0.05 c

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