Mathematics
Buddy44
11

Are the following lines perpendicular, parallel, or neither y=2x-4 3x+6y=18

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(2) Answers
Thebest11

Y=2x-4 becomes a slope of 2/1x-4 (basically). With 3x+6y=18 you subtract 3x from both sides. So now the equation should look like 6y=-3x+18. Then you divide all the numbers by six ( since you have to get the 'y' by itself). The equation then looks like; y=-3/6x+3, which reduces to y= -1/2x+3. Making the lines perpendicular.

Polieke

[latex]k:\ y=2x-4\ \ \ \Rightarrow\ \ \ m_1=2\\ \\l:\ 3x+6y=18\ \ \ \Rightarrow\ \ \ 6y=-3x+18\ /:6\ \ \ \ \Rightarrow\ \ \ y=- \frac{3}{6} x+3\\ \\.\ \ \ \ y=- \frac{1}{2} x+3\ \ \ \Rightarrow\ \ \ m_2=- \frac{1}{2}\\ \\ m_1\cdot m_2=2\cdot (- \frac{1}{2})=-1\ \ \ \ \Rightarrow\ \ \ \ k\ \bot\ l\\ \\Ans.\ The\ lines\ are\ perpendicular.[/latex]

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