Mathematics
ashleyfoxy
19

An investment club invested part of $8000 at 10% annual interest the rest at 12%. If the annual income from these investments is $900, how much was invested at each rate

+1
(1) Answers
sxicidxl

let x be the amount invested  at 10% so the amount invested at 12 % =  (8000-x)    0.1x + 0.12(8000-x) = 900    0.1x - 0.12x = 900- 960    0.02x = 60      x   =  3000      @ 10%               8000 - 3000    =    5000     @ 12%

Add answer