DylanBossy
6

# A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest. Find the average angular acceleration of the turntable during the 0.5 s period. Answer in units of rad/s2

Well, the acceleration is the difference of speeds divided by the time period. $\frac{32.4}{0.5}=64.8rev/s^2$. One rev/s is $2\pi rad/s^2$, so our final result is $64.8*2\pi=407.15rad/s^2$.