Physics
DylanBossy
6

A turntable is designed to acquire an angular velocity of 32.4 rev/s in 0.5 s, starting from rest. Find the average angular acceleration of the turntable during the 0.5 s period. Answer in units of rad/s2

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(1) Answers
Skyheart

Well, the acceleration is the difference of speeds divided by the time period. [latex]\frac{32.4}{0.5}=64.8rev/s^2[/latex]. One rev/s is [latex]2\pi rad/s^2[/latex], so our final result is [latex]64.8*2\pi=407.15rad/s^2[/latex].

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