Physics
Rangata
9

A squirrel sitting on the ground starts to run with an acceleration of 5.1 m/s 2. How fast is the squirrel going after 0.25 seconds? A. 20.4 m/s B. 1.28 m/s C. 0.49 m/s D. 3.1 m/s

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(1) Answers
Tharu1988

initial speed = 0 final speed = v acceleration = 5.1  time taken = 0.25 v=u+at v=1.28 m /s

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