Physics
dreaira05
75

A rock is rolling down a hill. At position 1, its velocity is 2.0 m/s. Twelve seconds later, as it passes position 2, its velocity is 44.0 m/s. What is the acceleration of the rock? 42.0 m/s 2 3.7 m/s2 3.8 m/s2 3.5 m/s2

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(1) Answers
pooisgood

acceleration = change in velocity / time acceleration = (44 -2) /12 acceleration = 3.5

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