Mathematics
Yemen
22

A rectangle has a perimeter of 30 feet and an area of 50 square feet. What are the dimensions of the rectangle?

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(2) Answers
ajimene43

Perimeter of rectangle = 2L + 2W Area = L x W L x W = 50 2L + 2W = 30 There's a quick way to determine this. Find the factors of 50 as a product. 2 x 25, 5 x 10. We can use these factors as sides (dimensions). 2x2 + 2x25 = 4 + 50 = 54, incorrect factors. 2x5 + 2x10 = 10 + 20 = 30, correct. Your dimensions are 5 and 10.

kylieeeu

 5 ft x 10 ft.  (2) 5ft  + (2) 10ft  = 30 ft.  5 x 10 = 50 sq ft

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