A bus is traveling with a uniform acceleration of 2.75 meters/second2. If the initial velocity of the bus is 16.5 meters/second, what will its velocity be after 9.00 seconds?
(1) Answers
v=u+at v = 16.5 + (2.75)*(9) where v is the final speed u is the initial speed a is the acceleration t is the time v=41.25 m/s
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